5cos^2(3x+1)+2cos(3x+1)-1=0

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Solution for 5cos^2(3x+1)+2cos(3x+1)-1=0 equation:


Simplifying
5cos2(3x + 1) + 2cos(3x + 1) + -1 = 0

Reorder the terms:
5cos2(1 + 3x) + 2cos(3x + 1) + -1 = 0
(1 * 5cos2 + 3x * 5cos2) + 2cos(3x + 1) + -1 = 0
(5cos2 + 15cos2x) + 2cos(3x + 1) + -1 = 0

Reorder the terms:
5cos2 + 15cos2x + 2cos(1 + 3x) + -1 = 0
5cos2 + 15cos2x + (1 * 2cos + 3x * 2cos) + -1 = 0
5cos2 + 15cos2x + (2cos + 6cosx) + -1 = 0

Reorder the terms:
-1 + 2cos + 6cosx + 5cos2 + 15cos2x = 0

Solving
-1 + 2cos + 6cosx + 5cos2 + 15cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 2cos + 6cosx + 5cos2 + 1 + 15cos2x = 0 + 1

Reorder the terms:
-1 + 1 + 2cos + 6cosx + 5cos2 + 15cos2x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2cos + 6cosx + 5cos2 + 15cos2x = 0 + 1
2cos + 6cosx + 5cos2 + 15cos2x = 0 + 1

Combine like terms: 0 + 1 = 1
2cos + 6cosx + 5cos2 + 15cos2x = 1

Reorder the terms:
-1 + 2cos + 6cosx + 5cos2 + 15cos2x = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2cos + 6cosx + 5cos2 + 15cos2x = 0

The solution to this equation could not be determined.

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